707. Design Linked List
Design your implementation of the linked list. You can choose to use a singly or doubly linked list.
A node in a singly linked list should have two attributes: val and next. val is the value of the current node, and next is a pointer/reference to the next node.
If you want to use the doubly linked list, you will need one more attribute prev to indicate the previous node in the linked list. Assume all nodes in the linked list are 0-indexed.
Implement the MyLinkedList class:
MyLinkedList()Initializes theMyLinkedListobject.int get(int index)Get the value of theindexthnode in the linked list. If the index is invalid, return-1.void addAtHead(int val)Add a node of valuevalbefore the first element of the linked list. After the insertion, the new node will be the first node of the linked list.void addAtTail(int val)Append a node of valuevalas the last element of the linked list.void addAtIndex(int index, int val)Add a node of valuevalbefore theindexthnode in the linked list. Ifindexequals the length of the linked list, the node will be appended to the end of the linked list. Ifindexis greater than the length, the node will not be inserted.void deleteAtIndex(int index)Delete theindexthnode in the linked list, if the index is valid.
Example 1:
Input
["MyLinkedList", "addAtHead", "addAtTail", "addAtIndex", "get", "deleteAtIndex", "get"]
[[], [1], [3], [1, 2], [1], [1], [1]]
Output
[null, null, null, null, 2, null, 3]
Explanation
MyLinkedList myLinkedList = new MyLinkedList();
myLinkedList.addAtHead(1);
myLinkedList.addAtTail(3);
myLinkedList.addAtIndex(1, 2); // linked list becomes 1->2->3
myLinkedList.get(1); // return 2
myLinkedList.deleteAtIndex(1); // now the linked list is 1->3
myLinkedList.get(1); // return 3
Constraints:
0 <= index, val <= 1000- Please do not use the built-in LinkedList library.
- At most
2000calls will be made toget,addAtHead,addAtTail,addAtIndexanddeleteAtIndex.
Solution:
class MyLinkedList {
int size;
ListNode head;
public MyLinkedList() {
size = 0;
head = new ListNode(-1);
}
public int get(int index) {
if (index < 0 || index >= size){
return -1;
}
// -1 0 2
// head -> n1->n2
// cur
ListNode cur = head;
for (int i = 0; i < index + 1; i++){ // Get the value of the indexth node in the linked list
cur = cur.next;
}
return cur.val;
}
public void addAtHead(int val) {
addAtIndex(0, val);
}
public void addAtTail(int val) {
addAtIndex(size, val);
}
public void addAtIndex(int index, int val) {
if (index > size){
return;
}
index = Math.max(0, index);
size++;
ListNode cur = head;
for (int i = 0; i < index; i++){
cur = cur.next;
}
ListNode toAdd = new ListNode(val);
toAdd.next = cur.next;
cur.next = toAdd;
}
public void deleteAtIndex(int index) {
if (index < 0 || index >= size){
return;
}
size--;
ListNode cur = head;
for (int i = 0; i < index; i++){
cur = cur.next;
}
cur.next = cur.next.next;
}
}
class ListNode{
int val;
ListNode next;
public ListNode(int val){
this.val = val;
}
}
/**
* Your MyLinkedList object will be instantiated and called as such:
* MyLinkedList obj = new MyLinkedList();
* int param_1 = obj.get(index);
* obj.addAtHead(val);
* obj.addAtTail(val);
* obj.addAtIndex(index,val);
* obj.deleteAtIndex(index);
*/
Java 中实现使用双向链表